(x^2-1)/(3x^2-2x-1)=0

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Solution for (x^2-1)/(3x^2-2x-1)=0 equation:


D( x )

3*x^2-(2*x)-1 = 0

3*x^2-(2*x)-1 = 0

3*x^2-(2*x)-1 = 0

3*x^2-2*x-1 = 0

3*x^2-2*x-1 = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(2*3) or x = (2-16^(1/2))/(2*3)

x = 1 or x = -1/3

x in (-oo:-1/3) U (-1/3:1) U (1:+oo)

(x^2-1)/(3*x^2-(2*x)-1) = 0

(x^2-1)/(3*x^2-2*x-1) = 0

3*x^2-2*x-1 = 0

3*x^2-2*x-1 = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(2*3) or x = (2-16^(1/2))/(2*3)

x = 1 or x = -1/3

(x+1/3)*(x-1) = 0

(x^2-1)/((x+1/3)*(x-1)) = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in { 1}

x = -1

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